Correct Answer: Option B

Explanation

Given:

Concentration of CaBr\(_2\) = 20 gdm\(^{-3}\)

              CaBr\(_2\) ⇌  Ca\(^{2+}\)  +   2 Br\(^-\)

                 1mole                     2moles

(a) Molarity (Molar concentration) of CaBr\(_2\)  = \(\frac{Mass concentration}{Molar mass}\)

Molar mass of  CaBr\(_2\) = 40 + (80 x 2) = 200g/mol

    Molarity of CaBr\(_2\)  = \(\frac{20}{200}\)

                                         = 0.100M

(b) Since 1mole of  CaBr\(_2\) produces 2moles of Br\(^-\)

     Molarity of 2Br\(^-\) = 2 x 0.100

                                    = 0.200M

The molarity of the solution with respect to calcium bromide and bromide ions are 0.10 and 0.20 respectively.

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