Using 50 cm\(^3\) of 1 M potassium hydroxide and 100 cm\(^3\) of 1 M tetraoxosulphate (VI) acid, calculate the respective volumes in cm\(^3\) of base and acid that would be required to produce the maximum amount of potassium tetraoxosulphate (IV) [K = 39, S = 32, O = 16, H = 1]
a
50, 50
b
25, 50
c
50, 25
d
25, 25
Explanation
Correct Option
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Discussions (11)
SammyKush011
5 years ago
2KOH + H2SO4 > K2SO4 + 2H2O
2 vol : 1 vol
50cm³ : 25cm³ : 25 : 50
maximum volume of base 50
max vol of acid 25
= 50.25 C
Adannewi
10 years ago
2KOH + H2SO4--> K2SO4 +2H2O
50cm of 2KOH will require 25cm of H2SO4.... The correct answer is C and not D
