Elements X and Y have electronic configurations 1s\(^2\)2s\(^2\)2p\(^4\) and 1s\(^2\)2s\(^2\)2p\(^6\)3s\(^2\)3p\(^1\) respectively. When they combine, the formula of...

Elements X and Y have electronic configurations 1s\(^2\)2s\(^2\)2p\(^4\) and 1s\(^2\)2s\(^2\)2p\(^6\)3s\(^2\)3p\(^1\) respectively. When they combine, the formula of...

JAMB 1989

Elements X and Y have electronic configurations 1s\(^2\)2s\(^2\)2p\(^4\) and 1s\(^2\)2s\(^2\)2p\(^6\)3s\(^2\)3p\(^1\) respectively. When they combine, the formula of the compound formed is?

A. XY
B. YX
C. X₂Y₃
D. Y₂X₃

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Correct Answer: Option D

Explanation

\(\frac{\text{Element X}}{1s^22s^21p^4}\)

Valency of X is 2

\(\frac{\text{Element Y}}{1s^22s^22p^63s^23P^1}\)

valency of Y is 3

There is an exchange of valency when a compound is being formed. Hence, we have Y\(_2\)X\(_3\)

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