The minimum volume of oxygen required for the complete combustion of a mixture of 10cm 3 of CO and 15 cm 3 of H 2 is

a

25.0cm3

b

12.5 cm3

c

10.0 cm3

d

5.0cm3

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b

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Discussions (17)

SammyKush011
5 years ago

2Co + O2 > 2CO2
2vol: 1vol
10cm³ : 5cm³
2H2 + O2 > 2H2O
2vol: 1vol
15cm³ : 7.5cm³
minimum vol of O2 required = 5+7.5 = 12.5cm³

hopewilson16
6 years ago

CO +½ O2 = CO2
therefore for 10cm³ of
co we need 1/2 of 10cm = 5cm³ of O2
H2 + ½ O2 =H2O
therefore for 15cm³ of H2, we need 1/2of 15cm = 7.5cm of O2
* 5cm³ + 7.5cm³ = 12.5cm³ Ans

FAUSIZZY
7 years ago

Co +½ o2 = co2 for 10cm³
Then co needs 5cm³ de o2
H² + ½ o² =H2o for 15cm³
Then H² needs 7.5 de o2
* 5cm³ + 7.5cm³ = 12.5cm³

Mongrel
2 years ago
Image

Deksdaboss
2 years ago

The answer is A
double the 12.5cm3 to get theminimum value of 02

kemvic2003
2 months ago

H2CO3
2=3
15=x (cross multiply)
x=45/2
=22.5
So therefore X is equal to 22.5 And X is co 3
So the total volume that CO3 needs to complete the reaction is 22.5 that's the total volume that is meant to achieve the reaction but it is only 10 centimeter cube that we were given instead of 22.5 therefore the amount of volume needed to complete the reaction is 22.5 - 10 centimeter cube That is 12.5 centimeter cube.
That is our answer at 12.5 So 12.5 is the amount of volume needed to complete the reaction

1jenny
1 year ago

no answer

hafheez
7 years ago

B IS COWET

CBA
7 years ago

Wrong the answer is 12.5cm^3.

Gobbler
9 years ago

Please an explanation

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