The molar ratio of carbon to hydrogen of a volatile liquid compound is 1: 2. 0. 12 g of the liquid on evaporation at s.t.p. gave 32 cm3 of vapour. The molecular formula of the liquid is
[G.M.V =22.4 dm 3, C = 12, H = 1]
C 3 H 6
C 4H 8
C 5C 10
C 6H 12
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32/1000=0.032dm3
0.032dm³ -------- 0.12g
22.4dm³ -------- 0.12×22.4/0.032=84g
molar ratio of C=1 $ H=2
n(CH2)=84
n(12+2)=84
14n=84
n=84/14=6
C6H12

Molar ratio is 1:2 that is CH2 and we are finding the molecular formula the mass of the liquid=0.12
Volume of liquid at stp=32cm³ convert to dm³ you divide by 1000
That's =0.032
And the molar gas volume is 22.4
Then to find mole=volume(0.032)/molar gas volume(22.4)=0.00143mol
Then calculate for molar mass=mass of liquid(0.12)/mole(0.00143)=84
Then (CH2)n=84
(12+2)n=84
14n=84
n=6
(CH2)6
C6H12

The molar ratio of carbon to hydrogen of a volatile liquid compound is 1: 2. 0. 12 g of the liquid on evaporation at s.t.p. gave 32 cm3 of vapour. The molecular formula of the liquid is
[G.M.V =22.4 dm 3, C = 12,







