A gas occupies a volume of 30.0 dm\(^3\) at S.T.P. What volume would it occupy at 91\(^0\)C and 380 mm Hg?

AnnieVal

10 years ago

You were given v=30.0dm^3 at S.T.P(T=273, P=760mmHg) and was told to find v, if T=91degree and P=380mmHg.

V1=30dm^3, T1=273, P1=760mmHg, V2=?, T2=91+273=364, P2=380mmHg.

P1V1/T1=P2V2/T2

V2=P1V1T2/P2T1

V2=760*30*364/380*273

V2=80.0dm^3

AnnieVal

10 years ago

Here is an explanation:

You were given v=30.0dm^3 at S.T.P(T=273, P=760mmHg) and was told to find v, if T=91degree and P=380mmHg.

V1=30dm^3, T1=273, P1=760mmHg, V2=?, T2=91+273=364, P2=380mmHg.

P1V1/T1=P2V2/T2

V2=P1V1T2/P2T1

V2=760*30*364/380*273

V2=80.0dm^3

Excel242

4 years ago

p1v1/T1=p2V2/T2
V1=30dm3
p1= 760mmHg
T1= 273k
P2= 380mmhg
T2= 364k
V2=?
760*30/273=380*V2/T2
V2= 760*30*364/380*273
V2=8299200/103740
V2=80.0 dm3

jola3

10 years ago

Here is an explanation:

according to d Charles law...v1 is 30.00dm3 p1 is 380hhmg t1 is 91°c while d constant temperature and pressure be as 237k and 760hhmg which will rep. t2 and p2

>v1p1/t1=v2p2/t2

substitute d figures and solve u will get 80.0dm3 d final ans

Muheylele

5 years ago

P¹V¹/T¹=P²V²/T²

Donttouchme

1 year ago

explanation not available

Axel123

1 year ago

Error in the question

amafavour123

1 year ago

explanations are not available how will I know how to get the answers given to me?

Chibuikegerald60

10 years ago

Correct

Rhaybeccahmohyin

1 year ago

Combined Gas Law
P1V1/T1 = P2V2/T2
V1=30.0dm^3, V2= ?, T1=273k (at S.T.P), T2= 91+273k= 364k, P1=760mmHg (at S.T.P), P2=380mmHg
Formula: P1V1/T1 =P2V2/T2
Therfore V2 = P1V1T2/ P2T1= 760*30*364/380*273=
V2=80.0dm^3.„