Correct Answer: Option D

Explanation

Given:

V\(_1\) = 30.0 dm\(^3\) , T\(_1\) = 273K ,  P\(_1\) =  760 mmHg  (At S.T. P)

V\(_2\) = ? ,   T\(_2\) = 91 + 273= 364K ,  P\(_2\) =  380 mmHg

Using  \(\frac{{P_1}{V_1}}{T_1}\) =  \(\frac{{P_2}{V_2}}{T_2}\)

                       V\(_2\) = \(\frac{{P_1}{V_1}{T_2}}{{P_2}{T_1}}\)

                                   = \(\frac{{760}\times{30}\times{364}}{{380}\times{273}}\)

                                   = 80.0 dm\(^3\)

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