The empirical formula of an oxide of nitrogen containing 30.4 per cent of nitrogen is (N=14.0,O=16.0)

AngelSpicy

3 years ago

for futher explanation , refer ro New school chemistry by Osei Yaw Ababio.Page 34.

Anzyumoh

3 years ago

Total percentage=100%
percentage of N=30.4%
we subtract the percentage of N from 100 to get the percentage of O2.
therefore % of O2=69.6%

N. O
30.4. 69.6.
divide by Thier molar mases

30.4/14 69.6/16
= 2.17 4.35
divide through by the small number of the 2
= 2.17/2.17 4.35/2.17
= 1 2
therefore The molecular formula=NO2

Joyty

5 years ago

N=30•4
O=100-30.4=69.6

BabieGals

2 years ago

they said to find the empirical formula of oxide

hochezroyalacademy

5 months ago

great