12 g of solid protassium chlorate (KCIO) were added to 40 g of water and heated to dissolve all the solid. As the solution cools, crystals of potassium chlorate at 66 oC. The solubility of potassium chlorate at 66 oC is therefore?
66
33
10
20
30
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mass of solute = 12g
mass of solvent = 40g(40cm3) since water has a density of 1g/cm3
in dm3 = 40/1000 = 0.04dm3
Solubility = 12g/0.04dm3 = 300g/dm3
NO OPTION IS CORRECT
NO OPTION IS CORRECT
Answer couldn't have been in mol/dm3 since the atomic masses of K, Cl and O weren't given

Solubility is M/MM x 1000/V.
Mm of KClO = 39+ 35.5 + 16 =90.5
Volume= 40cm^3
So, Solubility=(12/90.5)x(1000/40)= 3.315g/dm^3
The answer isn't there

Absolutely correct "E"
this is calculation on solubility in grams of solvent per 100g.
Molarity is calculated in volume per 1000. CHECK THE TWO FORMULA

The selected answer is wrong:
Indicator Acid Side Neutral Alkaline Side Methyl Orange Pink Orange Yellow Litmus Red Purple Blue Phenolphthalein Colorless Colorless Pink
REF: understanding chemistry page 144



