Methanoic acid mixes with water in all proportions and has about the same boiling point as water which of the following methods would you adopt to obtain pure water from a mixture of stand, water and methanoic acid?
fractional distillation
filtration followed by distillation
neutralization with sodium hydroxide followed by distillation
esterification with ethanol followed by distillation
neutralization with sodium hydroxide followed by filtration
Explanation
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Here is an explanation:
The method of separation to be used is neutralization with sodium hydroxide followed by filtration. The question expresses water and methanoic acid as an azeotropic mixture (having similar boiling points) which when boiled or heated will appear as a constant boiling mixture and cannot be further seperated.
Methanoic acid is an acid which can undergo neutralization reaction with sodium hydroxide and therefore the sand can be filtered
Now, if we neutralize the mixture with sodium hydroxide, the products will be, sodium methanoate, water, and sand. At this point please be careful, sodium methanoate is a white powdery solid which is quite soluble in water. Therefore, filteration at this point will not obtain pure water but only obtain sand from the mixture and the water remaining will contain dissolved sodium methanoate.But applying direct distillation to sand, water, and dissolved sodium methanoate, will separate water from the mixture, leaving behind solid sodium methanoate and sand. Remember, our interest is to obtain pure water from the initial mixture.
c is d answer
The boiling point of methanoic acid is similar to that of water, which means that simple distillation will not separate water from the methanoic acid. Therefore, we need to use a process that can separate the water from the mixture that contains water, methanoic acid, and sand.
The correct answer is option C, neutralization with sodium hydroxide followed by distillation. The process of neutralization with sodium hydroxide will convert methanoic acid into its salt, sodium methanoate. Sodium methanoate is soluble in water, and sand, being insoluble, can be filtered out. The aqueous solution of sodium methanoate and water can be separated by distillation, as the boiling points of the two compounds are different. The boiling point of sodium methanoate is higher than that of water, so water can be easily obtained as a pure substance by distilling the mixture.
The best answer to this question is option A
Since boiling point of water is 100ยฐC and that of methanoic acid is 100.7ยฐC
So the best method is by distillation. When it begins to reach 100 degree, pure water begins to distill out leaving methanoic acid
The water can be collected via a tube
but the method ( option E) doesn't give you pure water it gives the mixture of a salt and water
Th answer is E guys distillation cannot be used here because the 2 mixtures are azeotropic
To obtain pure water from a mixture of sand, water and methanoic acid, you could first use filtration to remove the sand. Then, you could neutralize the methanoic acid with sodium hydroxide to form sodium methanoate and water. Finally, you could use distillation to separate the water from the sodium methanoate. So the correct answer would be C. Neutralization with sodium hydroxide followed by distillation.
Option E suggests neutralizing the methanoic acid with sodium hydroxide followed by filtration. While this would remove the sand and neutralize the methanoic acid, it would not separate the water from the sodium methanoate that is formed. Filtration can separate solids from liquids, but it cannot separate two liquids. So option E would not be an effective method to obtain pure water from a mixture of sand, water and methanoic acid.
the reaction will be
CH2O2 + NaOH = NaCHO2 + H2O
were sodium formate will be formed and because it dissolves in water distillation has to be carried out. so the answer is C
The mixture contains three things:
i. Sand (insoluble solid)
ii. Water
iii. Methanoic acid (HCOOH)
And we want to obtain pure water.
โฬฒ๐ฆโฬฒ๐โฬฒ๐ฒโฬฒ๐ฝโฬฒ โฬฒ๐ญโฬฒ โฬฒโโฬฒ โฬฒ๐ฅโฬฒ๐ฒโฬฒ๐บโฬฒ๐ผโฬฒ๐โฬฒ๐ฒโฬฒ โฬฒ๐โฬฒ๐ตโฬฒ๐ฒโฬฒ โฬฒ๐ฆโฬฒ๐ฎโฬฒ๐ปโฬฒ๐ฑ
Sand is insoluble in water, so it can be separated ๐ฒ๐ฎ๐๐ถ๐น๐ ๐ฏ๐ ๐ณ๐ถ๐น๐๐ฟ๐ฎ๐๐ถ๐ผ๐ป.
After filtration we are left with:
๐ช๐ฎ๐๐ฒ๐ฟ + ๐ ๐ฒ๐๐ต๐ฎ๐ป๐ผ๐ถ๐ฐ ๐ฎ๐ฐ๐ถ๐ฑ (๐ฏ๐ผ๐๐ต ๐น๐ถ๐พ๐๐ถ๐ฑ๐ ๐ฎ๐ป๐ฑ ๐ฏ๐ผ๐๐ต ๐บ๐ถ๐๐ฐ๐ถ๐ฏ๐น๐ฒ).
โฬฒ๐ฆโฬฒ๐โฬฒ๐ฒโฬฒ๐ฝโฬฒ โฬฒ๐ฎโฬฒ โฬฒโโฬฒ โฬฒ๐ฆโฬฒ๐ฒโฬฒ๐ฝโฬฒ๐ฎโฬฒ๐ฟโฬฒ๐ฎโฬฒ๐โฬฒ๐ฒโฬฒ โฬฒ๐ โฬฒ๐ฒโฬฒ๐โฬฒ๐ตโฬฒ๐ฎโฬฒ๐ปโฬฒ๐ผโฬฒ๐ถโฬฒ๐ฐโฬฒ โฬฒ๐โฬฒ๐ฐโฬฒ๐ถโฬฒ๐ฑโฬฒ โฬฒ๐ณโฬฒ๐ฟโฬฒ๐ผโฬฒ๐บโฬฒ โฬฒ๐ชโฬฒ๐ฎโฬฒ๐โฬฒ๐ฒโฬฒ๐ฟ
The question gives an important clue:
Methanoic acid mixes with water in all proportions and has about the same boiling point as water.
๐ช๐ฎ๐๐ฒ๐ฟ ๐ฏ๐ผ๐ถ๐น๐ ๐ฎ๐ ๐ญ๐ฌ๐ฌยฐ๐, ๐บ๐ฒ๐๐ต๐ฎ๐ป๐ผ๐ถ๐ฐ ๐ฎ๐ฐ๐ถ๐ฑ ๐ฎ๐ฟ๐ผ๐๐ป๐ฑ ๐ญ๐ฌ๐ญยฐ๐.
Because their boiling points are very close, simple or fractional distillation ๐๐ถ๐น๐น ๐ก๐ข๐ง ๐๐ฒ๐ฝ๐ฎ๐ฟ๐ฎ๐๐ฒ ๐๐ต๐ฒ๐บ ๐ฒ๐ณ๐ณ๐ฒ๐ฐ๐๐ถ๐๐ฒ๐น๐.
So we need another trick.
โฬฒ๐ฆโฬฒ๐โฬฒ๐ฒโฬฒ๐ฝโฬฒ โฬฒ๐ฏโฬฒ โฬฒโโฬฒ โฬฒ๐กโฬฒ๐ฒโฬฒ๐โฬฒ๐โฬฒ๐ฟโฬฒ๐ฎโฬฒ๐นโฬฒ๐ถโฬฒ๐โฬฒ๐ฎโฬฒ๐โฬฒ๐ถโฬฒ๐ผโฬฒ๐ป
Methanoic acid can react with sodium hydroxide (NaOH):
๐๐๐ข๐ข๐ + ๐ก๐ฎ๐ข๐ โ ๐๐๐ข๐ข๐ก๐ฎ + ๐โ๐ข
๐ง๐ต๐ถ๐ ๐ณ๐ผ๐ฟ๐บ๐ ๐๐ผ๐ฑ๐ถ๐๐บ ๐บ๐ฒ๐๐ต๐ฎ๐ป๐ผ๐ฎ๐๐ฒ, ๐๐ต๐ถ๐ฐ๐ต ๐ถ๐ ๐ฎ ๐ป๐ผ๐ป-๐๐ผ๐น๐ฎ๐๐ถ๐น๐ฒ ๐๐ฎ๐น๐.
Now the mixture contains:
Water and Sodium methanoate (non-volatile)
โฬฒ๐ฆโฬฒ๐โฬฒ๐ฒโฬฒ๐ฝโฬฒ โฬฒ๐ฐโฬฒ โฬฒโโฬฒ โฬฒ๐โฬฒ๐ถโฬฒ๐โฬฒ๐โฬฒ๐ถโฬฒ๐นโฬฒ๐นโฬฒ๐ฎโฬฒ๐โฬฒ๐ถโฬฒ๐ผโฬฒ๐ป
If we now distill, only ๐๐ฎ๐๐ฒ๐ฟ ๐๐ฎ๐ฝ๐ผ๐ฟ๐ถ๐๐ฒ๐ ๐ฎ๐ป๐ฑ ๐ถ๐ ๐ฐ๐ผ๐น๐น๐ฒ๐ฐ๐๐ฒ๐ฑ ๐ฎ๐ ๐ฝ๐๐ฟ๐ฒ ๐๐ฎ๐๐ฒ๐ฟ, ๐๐ต๐ถ๐น๐ฒ ๐๐ต๐ฒ ๐๐ฎ๐น๐ ๐ฟ๐ฒ๐บ๐ฎ๐ถ๐ป๐ ๐ฏ๐ฒ๐ต๐ถ๐ป๐ฑ.
Check the Options
A. Fractional distillation 
Boiling points are too close.
B. Filtration followed by distillation
Water and methanoic acid would distill together.
๐. ๐ก๐ฒ๐๐๐ฟ๐ฎ๐น๐ถ๐๐ฎ๐๐ถ๐ผ๐ป ๐๐ถ๐๐ต ๐๐ผ๐ฑ๐ถ๐๐บ ๐ต๐๐ฑ๐ฟ๐ผ๐
๐ถ๐ฑ๐ฒ ๐ณ๐ผ๐น๐น๐ผ๐๐ฒ๐ฑ ๐ฏ๐ ๐ฑ๐ถ๐๐๐ถ๐น๐น๐ฎ๐๐ถ๐ผ๐ป
๐๐ผ๐ฟ๐ฟ๐ฒ๐ฐ๐ ๐บ๐ฒ๐๐ต๐ผ๐ฑ.
D. Esterification with ethanol followed by distillation
Unnecessary and complicated.
E. Neutralization followed by filtration
The salt formed is soluble, so filtration won't separate it.
Answer z correct bcus both liquids r of close boiling pt. n in such situation fractional distillation z employed there by leaving sand in d rxn vessel.....optn (B) z wrong bcus ordinary distillatn can't seperate a soln of mix able liquids of close boiling pt....wah I fink anyways!!!
To obtain pure water we have to first neutralizes the acid which leaves us with sand,water and salt. To get pure water distillation is the best so the answer is option c
It is C
neutralization first HCOOH +NaOH-->HCOONa +H2O
followed by distillation
dont forget the HCOONa formed is soluble but not as volatile as HCOOH.. which will make distillation possible
E. neutralization with sodium hydroxide followed by filtration
Explanation:
Neutralization with sodium hydroxide (NaOH) would convert methanoic acid (HCOOH) into sodium methanoate (HCOONa), which is water-soluble. Filtration after neutralization would then separate the water-soluble sodium methanoate from the sand, leaving behind pure water.
This method effectively removes both the methanoic acid and the sand from the water, yielding pure water as the final product. Therefore, option E is the correct answer.
