The oxidation state of manganese in potassium permanganate is

Afolabiazeez814

7 years ago

Oxidation state of Mn in KMnO4=1+x+4 (-2)=0
1+x-8=0
x=8-1
x=7

ThankGodNwaoha

7 years ago

Kmno4
oxidation state of element(k=+1,mn=?, O=-2
+1+mn+(-2x4)=0
mn=8-1
mn=+7

justiceeby7

3 years ago

Potassium permanganate= KMnO3
KMnO4= 0
{K=+1, Mn= x, O= -2}
K + Mn + O4 = 0
+1+ x +(-2×4) = 0
+1 +x -8 = 0
x = -1 + 8
x = 7
potassium permanganate (vii)

taiwofrancis1

3 years ago

kmno4 = +1 +mn +(-2)x4
1+mn+-8=0
mn=8-1
mn = +7