A compound contains 40.0% C, 6.7% H 53.3% O. If the molecular mass of the compound is 180, its molecular formula is [C =12, H =1,O]

a

CH2O

b

C3H6O3

c

C6H6O3

d

C6H12O6

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d

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Ninny
9 years ago

C=40.0÷12

H=6.7÷1

O=53.3÷16

then

C=3.3,H=6.7,O=3.3 then divide all three by d smallest Which is 3.3 then

C=1,H=2,O=1=CH2O



molecular formula 12+1+16=180

180÷29=6

so C6H12O6

LuvQueen
4 years ago

Pls hw did u get 29

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