CO(g) + H\(_2\) O\(_{(g)}\) → CO\(_{2(g)}\) + H\(_{2(g)}\)
Calculate the standard heat change of the reaction above, if the standard enthalpies of formation of CO\(_{2(g)}\), H\(_2\)O\(_{(g)}\) and CO\(_{(g)}\) in kJmol\(^{-1}\) are - 394, -242 and - 110 respectively.

mc.Jeremiah

6 years ago

The answer is wrong
H product-H reactant
-394-(-242-110)
-394-(-352)
-394+352
-42 is the correct answer

Gobbler

9 years ago

It's -42kj/mol.

Stock

10 years ago

It's -42kj.

Stock

10 years ago

Enthalpy Change=Heat of products(-)Heat of reactants.-394(-)-242-110.-394+352=-42kj/mol."C" is wrong and "D" is correct.

GloryAbiola

6 years ago

pls i'm confused,is it C or D?

KingKelvinakashadow

5 years ago

It -42kj/mol

Austine500

9 years ago

The ans is -42kj/mol

TheHound

9 years ago

@chubby_precious what kind of mathematical operation(-352+394=42kj/mol) is it?

Chiamaka Ibekwe

9 years ago

hey,Chubby precious is right! considering our given product and reactant

TeReTeRe

7 years ago

How could this website possibly choose C?

GloryAbiola

6 years ago

i don't really understand the topic, ENERGY AND CHEMICAL REACTIONS

OG117

6 years ago

i chose b whic is right but i was failed