During a titration experiment, 0.05 moles of carbon (lV) oxide is liberated. What is the volume of gas liberated?

Light Asa

9 years ago

Here is an explanation:

Amount In Mole=volume/molar Volume Volume=amount In Mole*molar Volume(22.4dm^3) 0.05*22.4=1.12dm^3

Treasure481

1 year ago

is the 22.4dm a constant?

Lanre010

2 years ago

mole = 0.05mol
M.V.G= 22.4dm^-3
V=?
mole = volume/M.V.G
mole×M.V.G=Volume
Volume=0.05×22.4
Volume= 1.12dm^-3

Anela

1 year ago

OR
If;1 mol. - 22.4
0.05mol. - x

=22.4×0.05
=1.12÷1= 1.12(ans)


Recall;22.4 is a constant

Lazy_scribble

5 years ago

okay

Odemosad

1 year ago

Moles = Vol. / Molar Vol.
Vol = 0.05 * 22.4
= 1.12 dm³

Danonso

4 years ago

this is wrong the answer is meant to be 'D'
are you guys okay at all?