2H_2(g) + O_2(g) → 2H₂ O_(g)
In the reaction above, what volume of hydrogen would be left over when 300 cm³ of oxygen and 1000 cm³ of hydrogen are exploded in a sealed tube?

Kosoronyi

6 years ago

2H2(g) + O2(g) → 2H2 O(g)
2 : 1 : 2
If oxgen is 300...den hydrogen= 300 *2
600 : 300 :600
So the remaining/left over would be
1000cm3 of hydrogen - used gas
1000-600=400cm3

Johncak316

3 years ago

ER LR
2H₂(g) + O₂(g) ---> 2H₂0(g) NB 1vol of H₂
= 500cm³
1vol of 0₂
= 300cm³
2vol + 1vol ---> 2vol
(2⨯300cm³) + (1⨯300cm³) ---> (2⨯300cm³)
600cm³ + 300cm³ --> 600cm³
Thus, the unused or left volume of H₂ gas is 1000cm³ - 600cm³ = 400cm³
Note that, H₂ gas is the Excess reactant while O₂ gas is the limiting reactant or reagent that is why all of it has been used up. The left over for O₂ gas is 0cm³

seyioke12345

2 months ago

Wow