How many atoms are present in 6.0g of magnesium?
[Mg = 24, N_A = 6.02 x 10²³ mol^-1]

julius97

9 years ago

No of atom = No of mole * Avogadro constant



No of mole = mass / molar mass

= 6 / 24

= 0.25mol



No of atom = 0.25 * 6.02 * 10^25

= 1.51*10^23

JoyceOgo

3 years ago

mass of Mg = 24g
mass of Mg given = 6.0g
mol = 6.02×10²³
24g of Mg ------ 6.02×10²³
6.0g of Mg ------- x cross multiply
6.0× 6.02×10²³ ÷ 24
x= 1.51×10²³

Pelumi Oluwabidemi 12

11 years ago

1 mole of an element is no of avogadros i.e 6.02x10E23

mole:mas23s/molar mass

6.0/24 0.25

0.25x6.02x10E23

1.51x10E

charisnova2

3 months ago

hi

ibnatuhajar

2 months ago

***

odsmart

1 year ago

mole=m/mm
mole=6/24
mole=0.25

mole=no of atom /6.02*10^23
0.25=x/6.02*10^23
x=0.25*6.02*10^23
x=1.51*10^23

Dalonise05

2 months ago

(mass/molar mass) * avogadro's number