Three drops of a 1.0 mol dm-3 solution of HCl was added to 20 cm3 of a solution of pH6.4. The pH of the resulting solution will be

a

close to that of pure water

b

less than 6.4

c

greater than 6.4

d

unaltered

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Explanation

Correct Option
b

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Discussions (5)

ICEDOK
5 years ago

Yes my school is right because the three drops of 1.0mol dm3 of HCL will increase the acidity of the resulting solution

Son1
2 years ago

B is correct less than 6.4

Egieb_z
4 years ago

Hmm, my school I can't express how wrong that answer is. pH =-log(H+),
pH of HCL =-log(1)
= 0
So the pH remains unaltered

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