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The mass of silver deposited when a current of 10A is passed through a solution of...

Chemistry
JAMB 2004

The mass of silver deposited when a current of 10A is passed through a solution of silver salt for 4830s is
[Ag = 108, 1F = 96500 Cmol-1]

  • A. 108.0g
  • B. 54.0g
  • C. 27.0g
  • D. 13.5g
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Correct Answer: Option B
Explanation

Ag\(^+\) + e\(^-\) → Ag
If  96500 C deposited 108g of Ag
∴ 10 x 4830C will deposit Xg of Ag
X = \(\frac{{108}\times{4830}\times{10}}{96500}\)

X = 54.06g

There is an explanation video available below.


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Explanation Video

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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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Post UTME Past Questions Agent
Your School's Whatsapp Group - Join Us now
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Post UTME Past Questions Agent
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