What volume of 0.5 mol dm\(^{-3}\) H\(_2\)SO\(_4\) will exactly neutralize 20cm\(^3\) of 0.1 mol dm\(^{-3}\) NaOH solution?

tyjesma

11 years ago

From the neutralization reaction Formula»»»CaVa/CbVb=na/nb....when the equation is banlaced we get----------» » »2 NaOH + H2So4 = Na2So4 + 2 H2O...Ca=0.5, Va=?, Cb=0.1, Vb=20, na=1, nb=2...when we substitute, we get

(0.5 * Va)/(0.1 * 20) = 1/2

∴ Va = 2.0cm

sulaimon192

11 years ago

correct