The solubility in moldm\(^{-3}\) of 20g of CuSO\(_4\) dissolved in 100g of water at 180\(^o\)C is
[Cu = 64, S = 32, O =16]
0.13
0.25
1.25
2.00
Explanation
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Cu= 64 S=32, O=16 molar mass of CuSO4 = (64+32+4(16)) =160
Solubility = mass/molarmass X 1000/volume
20/160 X 1000/100 = 20/16 = 1.25

20g CuSO4---------------100
X? g ----------------------------1000
= 20*1000/100, =20000/100
=200.
conc. in moldm-3 = conc.gdm-3/ molar mass of CuSO4 = 200/160 =1.25moldm-3

Reacting mass of CUSO4 is 20g
mm of CUSO4 = 160g
mole is m/mm = rm/mm
= 20/160 = 0.125
100g of water dissolves 0.125moles of CUSO4
1000cm³ of water will dissolve (1000/100) × 0.125 = 125moldm³


Pls hw will u know dat u will use 4 to times 16 instead of 3 pls
Explain to me if u know it ooo

Sol=n*stndvol/vol...n=m/Mm...m=20, Mm of (CuSO4)=160, V=100, & stndvol=1000...therefore solubility=20*1000/160*100 -------» 20000/16000= 1.25

m/mm ×1000/vol.
m= 20
mm=CuSO4(64+32+64=160)
vol.= 100
20/160 × 1000/100
= 20000/16000
=1.25(ANS)


