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The solubility in moldm\(^{-3}\) of 20g of CuSO\(_4\) dissolved in 100g of water at 180\(^o\)C is...

Chemistry
JAMB 2004

The solubility in moldm\(^{-3}\) of 20g of CuSO\(_4\) dissolved in 100g of water at 180\(^o\)C is
[Cu = 64, S = 32, O =16]

  • A. 0.13
  • B. 0.25
  • C. 1.25
  • D. 2.00
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Correct Answer: Option C
Explanation

Relative molecular mass of CuSO\(_4\) = 64 + 32 + (16 x 4) = 160
The number of moles of CuSO\(_4\) = \(\frac{mass}{Molar mass}\)

                                                          = \(\frac{20}{160}\)

                                                       n = 0.125 mole
100g of water dissolved 0.125mole of CuSO\(_4\)
100g of water will dissolve \(\frac{0.125}{100}\times{1000}\)

                                            Solubility = 1.25 moldm\(^{-3}\)

Alternatively, 

Solubility = Number of moles of solute x  \(\frac{1000}{Volume of solvent}\)

But Number of moles of solute = \(\frac{mass}{molar mass}\) = \(\frac{20}{160}\) = 0.125 moles

Solubility = Number of moles of solute x  \(\frac{1000}{Volume of solvent}\)

Solubility = 0.125 x  \(\frac{1000}{100}\)

               = 1.25 moldm\(^{-3}\)

There is an explanation video available below.


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