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\(^{226}\)\(_{88}\)Ra → \(^x\)\(_{86}\)Rn + α - particle What is the value of x in the...

Chemistry
JAMB 2004

\(^{226}\)\(_{88}\)Ra → \(^x\)\(_{86}\)Rn + α - particle
What is the value of x in the nuclear reaction above?

  • A. 220
  • B. 222
  • C. 226
  • D. 227
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Correct Answer: Option B
Explanation

α - particle is represented by He atom with mass number of 4 and atomic number of 2. Thus, try to balance the mass number and atomic number of both Ra and Rn by subtracting 4 from 226 i.e (226 - 4) and subtracting 2 from 88 i.e (88 - 2 = 86 ).

\(^{226}\)\(_{88}\)Ra → \(^{222}\)\(_{86}\)Rn + \(^4\)\(_2\)He (α - particle)

There is an explanation video available below.


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Explanation Video

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