A compound contains 40.0% carbon 6.7% hydrogen and 53.3% oxygen. If the molar mass of the compound is 180, find the molecular formula.
[H = 1, C = 12, O = 16]

professorkoko

11 years ago

THIS IS EMPIRICAL CALCULATION

Carbon(C) =40% Hydrogen(H) =6.7% Oxygen(O) =53.3%

STEP 1: Divide by the Relative Atomic Mass(RAM)

Carbon%(C) 40/12 = 3.33

Hydrogen%(H) 6.7/1 = 6.7

Oxygen% (O)53.3/16 = 3.33

STEP 2: Divide the num. by the smallest value

Carbon(C) = 3.33/3.33 = 1

Hydrogen(H) = 6.7/3.33 = 2

Oxygen(O) = 3.33/3.33 = 1

C1 H2 O1 RATIO: CH20

But Relative Atomic Mass is 180

Therefore:. (CH2O)n = 180

(12 + 2 + 16)~n = 180

30n = 180

n = 6

= C6H12O6

aderemidebbie

1 year ago

pls how do you get 180