ethanedioic acid
ethanal
ethylethanoate
ethanoic acid
Explanation
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When ethanol react with k2cr207 it gives ethanal,but in excess k2cr207 it gives ethanoic
Primary alcohols can be oxidised to either aldehydes or carboxylic acids depending on the reaction conditions. In the case of the formation of carboxylic acids, the alcohol is first oxidised to an aldehyde which is then oxidised further to the acid.
Partial oxidation to aldehydes
You get an aldehyde if you use an excess of the alcohol, and distil off the aldehyde as soon as it forms.
The excess of the alcohol means that there isn't enough oxidising agent present to carry out the second stage. Removing the aldehyde as soon as it is formed means that it doesn't hang around waiting to be oxidised anyway!
Full oxidation to carboxylic acids
You need to use an excess of the oxidising agent and make sure that the aldehyde formed as the half-way product stays in the mixture.
The alcohol is heated under reflux with an excess of the oxidising agent. When the reaction is complete, the carboxylic acid is distilled off.
Since the question said excess k2cro2,the answer should be ethanoic acid.
This is an oxidation reaction of alkanol.Generally primary alkanol oxidize to alkanal and finally to alkanoic acid wen d oxidizing agent is in excess.Ethanol is a primary alkanol,from d question,oxidizing agent is in excess so ethanol will oxidize to gv ethanoic acid and not ethanal b'cos of excess oxidizing agent...option C is correct
Dat kul my bros,d real answer is c cos oxidation of p-alkanol gives R-cho nd finall R-cooh.nd s-alkanol gives R2-co i.e alkanone
