When ethene, C\(_2\)H\(_4\) reacts with hydrogen bromide (HBr), the product is bromoethane (C\(_2\)H\(_5\)Br):
C\(_2\)H\(_4\) + HBr → C\(_2\)H\(_5\)Br
This reaction is an addition reaction where HBr adds across the double bond of ethene:
There is an explanation video available below.
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