It forms tetraoxosulphate (VI) acid with water
It is an odourless gas
It is an acid anhydride
It forms white precipitate with acidified barium chloride
Explanation
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You guys are getting it all wrong. Sulphur (IV) oxide is not SO4^-2, it is SO3^2-. The most correct answer is C) it is an acid hydride.
The correct statement regarding sulfur dioxide (sulfur (IV) oxide) is:
D. It forms a white precipitate with acidified barium chloride.
When sulfur dioxide reacts with acidified barium chloride, it forms a white precipitate of barium sulfate. This reaction is often used as a test for the presence of sulfate ions in a solution.
The other options are incorrect:
A. Sulfur dioxide does not form tetraoxosulfate (VI) acid (H2SO4) with water. That is a property of sulfur trioxide.
B. Sulfur dioxide has a pungent odor.
C. Sulfur dioxide is not classified as an acid hydride. It is acidic in nature when dissolved in water, but it's not a classic example of an acid hydride.
ok yes I was wrong, it said H2SO4 with water as in products are H2SO4+H2O so the corr ans is c.
Options A and D describes the sulphate ion, SO4^2-, this is sulphur (VI) oxide. The sulphur (IV) oxide is also known as sulphite ion. Option B is incorrect because sulphur dioxide or Sulphur (IV) oxide has a pungent odour.
Everyone should be able to distinguish between these two gases with their oxidation numbers which influences their naming. Myschool, please verify the answer to this question
H2O(g) + SO4(g) > H2SO4 (aq). What then is this reaction, pls u guys shud stop this rubbish. Deception wont take u anywhere. most folks are hoping 4 ur correction.
