A change in temperature of a saturated solution disturb the equilibrium between the
Dissolved solute and the solvent
Solvent and undissolved solute
Dissolved solute and undissolved solute
Dissolved solute and the solution
Explanation
Video Explanation
Post your Contribution
Discussions (5)
the answer is 'c' because in a saturated solution,the dissolve solutes and the undissolved solutes are in equilibrium at a particular temperature..any change in temperature will disturb this equilibrium
Change in temperature of a saturated solution can disturb the equilibrium between the dissolved solute and the undissolved solute (if present). When temperature increases, the solubility of most solids tends to increase as well, causing more solute to dissolve. Conversely, when temperature decreases, solubility often decreases, leading to some dissolved solute precipitating out of the solution. This disrupts the equilibrium between the dissolved and undissolved solute, shifting it in the direction that helps reestablish equilibrium according to Le Chatelier's principle.
Firstly C is the answer cause a saturated solution contains dissolved solute at a particular temperature in the presence of undissolved solute
So in equilibrium the presence of undissolved and dissolved particle are at a particular temperature
The answer is A a saturated solution contains no undissolved solute but contains maximum number of dissolved solutes in a solution
No, the answer is A. A saturated solution is a chemical solution containing the maximum saturated of a solute dissolved in the solvent. Additional solute will not dissolve in a saturated solution.
