What mass of K₂CrO₄ is required to prepare 250cm³ of 0.020 mol dm³ solution?
[K₂CrO₄ = 194.2g mol^-1]

decole3

12 years ago

n=conc*volume=250*0.020/1000=0.005.n z also =mass/molar mass,dat implies,mass=n*molar mass=0.005*194.2=0.971

HighestscorerLawy

1 year ago

Just use the formula solubility = mass/molar mass * 1000 /volume . You will get the answer .

MATER1

5 months ago

The answer is correct

r65dg1

1 month ago

i don't understand the solution

mmesoprecious

11 years ago

very correct