3Cu + pHNO3 →3Cu(NO)2 + 4H2 O + xNO
In the equation above, the values of p and x respectively are
1 and 3
2 and 3
6 and 2
8 and 2
Explanation
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3Cu + pHNO3 β3Cu(NO)2 + 4H2O + xNO
Notice:* 3cu is on both sides(balance)...*on d right side 8hydrogen(2 balance add 8 to d left β hand side...d equation will look lyk dis π
3Cu + p=8HNO3 β3Cu(NO)2 + 4H2O + xNO)
πObserve d above equation carefully:*8 nitrogen on d left and 7 on d right...2 balance add 2 to d right hand side...d equation will look lyk disπ
3Cu + p=8HNO3 β3Cu(NO)2 + 4H2O + x=2NO)
Finally:24oxygen on d left while 12 oxygen on d right hand side...it is obvious dis equation isn't balanced at all...but lemme tell u a little secret jamb are actually very tricky and can make one spend more than 12 minutes looking so confused and perplexed on a question which is very bad...2 make things easier and faster without thinking excessively when writing jamb cuz time ain't our friend...we just have 2 follow their instructions given in d exam and follow it judiciously for example π
3Cu + pHNO3 β3Cu(NO)2 + 4H2 O + xNO
In the equation above, the values of p and x respectively are
A. 1 and 3
B. 2 and 3
C. 6 and 2
D. 8 and 2
It's obvious d ansa can be A,B or C...cuz observing d number of hydrogen which is 8 on d right hand side...so with dat little clue u can say d ansa is D which is 8 and 2 respectively π... hope dis helpsπ

The selected answer is wrong:
quetion 34,oxygen is 24 on the left hand side and 12 on the right hand side i need a workings 4 this question

3Cu + pHNO3 β3Cu(NO3)2 + 4H2 O + xNO
In the equation above, the values of p and x respectively are
A.1 and 3
B.2 and 3
C.6 and 2
D.8 and 2 
this is the correct question and the correct answer.. myschool made a mistake.
Cu+2 + NO3Β²- >> Cu(NO3)2.



