A fixed mass of gas has a volume of 92\(cm^3\) at 3ºC. What will be its volume at 18ºC if the pressure remains constant?

Don2098980

2 years ago

To solve this problem, you can use Charles's Law, which states that the volume of a given mass of gas is directly proportional to its absolute temperature, provided the pressure remains constant.

The formula for Charles's Law is:

\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]

Where:
- \( V_1 \) is the initial volume of the gas,
- \( T_1 \) is the initial temperature of the gas in Kelvin,
- \( V_2 \) is the final volume of the gas,
- \( T_2 \) is the final temperature of the gas in Kelvin.

First, you need to convert the temperatures to Kelvin using the equation:

\[ T_{\text{Kelvin}} = T_{\text{Celsius}} + 273.15 \]

Given that the initial volume \( V_1 = 92 \, \text{cm}^3 \) and the initial temperature \( T_1 = 3^\circ \text{C} \), you can convert \( T_1 \) to Kelvin:

\[ T_{1, \text{Kelvin}} = 3 + 273.15 \]

Now, you want to find the final volume \( V_2 \) when the final temperature \( T_2 = 18^\circ \text{C} \). Convert \( T_2 \) to Kelvin:

\[ T_{2, \text{Kelvin}} = 18 + 273.15 \]

Now, you can rearrange Charles's Law to solve for \( V_2 \):

\[ V_2 = \frac{V_1 \cdot T_{2, \text{Kelvin}}}{T_{1, \text{Kelvin}}} \]

Plug in the values:

\[ V_2 = \frac{92 \cdot (18 + 273.15)}{(3 + 273.15)} \]

Now, calculate the result to find the final volume \( V_2 \). 96.99728408, the answer was very confuse 97.0

1123da

4 months ago

this i don't understand at all cos what I calculate here is difference from this

Sikirublaze1995

11 years ago

Where is 273 gotten from that you used in getting T1?

Sikirublaze1995

11 years ago

I dont just understand this solving.. Please put me through pals

Don2098980

2 years ago

A fixed mass of gas has a volume of 92cm3 at 3ºC. What will be its volume at 18ºC if the pressure remains constant?

alexobi20

4 years ago

The solving is not correct

judsonandrey2012

10 years ago

It's very correct... 273 is gotten from the conversion of °C to kelvin

alexobi20

5 years ago

the answer is b
V2=(92×276)/291
V2=87.3cm³

Don2098980

2 years ago

The answer is B 87.3cm3

Don2098980

2 years ago

The answer is 87.3 cm3 B

Vikkiegreen

9 years ago

I don't think cnversin is needed since they are both in Celsius

Don2098980

2 years ago

Without using Kevin equation To find the volume of the gas at 18ºC, we can use the Charles's Law, which states that the volume of a gas is directly proportional to its temperature, assuming the pressure remains constant.

To solve this problem, we need to use the formula:

(V1 / T1) = (V2 / T2)

Where:
V1 = initial volume of the gas
T1 = initial temperature of the gas
V2 = final volume of the gas (what we want to find)
T2 = final temperature of the gas

In this case, the initial volume (V1) is given as 92 cm3 and the initial temperature (T1) is given as 3ºC. We want to find the final volume (V2) at 18ºC.

Let's plug in the values into the formula:

(92 / 3) = (V2 / 18)

To find V2, we can cross multiply and solve for V2:

3 * V2 = 92 * 18
V2 = (92 * 18) / 3
V2 = 552 cm3

Therefore, the volume of the gas at 18ºC, assuming the pressure remains constant, is 552 cm3.

So, the correct answer is option C. 552.0 cm3.