A red precipitate of copper (I) carbide is formed when ammonium solution of copper (I) chloride is introduced into

a

CH3CH2CH2CH3

b

CH2 = CH - CH2CH3

c

HC≡CH

d

CH3 - C = C - CH3

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Explanation

Correct Option
c

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Discussions (11)

kekezeze
9 years ago

Myschool you made a mistake the answer is c but you put but1ene instead of but1eyn because only terminal alkynes undergo that reaction the answer isn't d which is also meant to be an alkynes because it isn't terminla. In case your wondering terminal alkynes or Allen r the ones that have their double or triple bond on the last carbon atom .

eazi.lyon
5 years ago

b

kekezeze
9 years ago

Myschool you made a mistake the answer is c but you put but1ene instead of but1eyn because only terminal alkynes undergo that reaction the answer isn't d which is also meant to be an alkynes because it isn't terminal. In case your wondering terminal alkynes or Alkenes r the ones that have their double or triple bond on their last carbon atom .

Davidloove
13 years ago

Yep,methylprop-1-ene which is an isomer of buthyne.

godst22
11 years ago

that option should have been a triple bond if u ask me

Ekwokk
1 year ago

yeah substitution rxn

Dbest01
2 years ago

yes the answer is definitely correct cause only alkynes undergo reaction with copper 1 carbide nd also with ammonical silver u can also use it to distinguish it from alkanes and alkenes

soloskino
12 years ago

No,the answer isn't C but D because the reaction only works with compounds with triple bonds which is not in C but rather in D because the bond between the 2nd and 3rd carbon in D should be a triple bond not a double bond,making D the correct option.

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