25cm\(^3\) of a 0.2 mol dm\(^3\) solution of Na\(_2\)CO\(_3\) requires 20 cm\(^3\) of a solution of HCl for neutralization. The concentration of the HCl solution is

Itzveceeblast

7 years ago

Na2CO3 + 2HCl ➡ 2NaCl + H2O +CO2
Ca=? Va=20cm3
Cb=0.2mol/dm3 Vb=25cm3
na=2. nb=1
Ca=CbxVbxna/Vaxnb
= 0.2x25x2/20x1
= 0.5mol/dm3

Evanzdgenius

10 years ago

Here is an explanation:

NA2CO3 + 2HCL->2NACL+H2O+CO2

1 : 2

CAVA=NA/CBVB=NB

CA*20=2

0.2*5=1

crossmultiply

.'.ca=o.5mol/dm3

olunikki

13 years ago

1st write d chem equa Na2CO3 +2HCL>2NACL+H20+CO2.recal {CaVa}/{CbVb}=na/nb.Ca is ?,Va=20,na=2 frm d equa,Cb=0.2,vb=25,nb=1.substitute it nd u wil get ur ans

papper

5 years ago

ya A is d ans

Abrahamgentle6

10 years ago

k

DesmondBuwaX

1 week ago

men always forget it