The solubility of a salt of molar mass 101g at 20oC is 0.34 mol dm-3....

JAMB 2002

The solubility of a salt of molar mass 101g at 20^oC is 0.34 mol dm^-3. If 3.40g of the salt is dissolved completely in 250cm³ of water in a beaker, the resulting solution is

A. A suspension
B. Saturated
C. Unsaturated
D. Supersaturated

Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts

WAEC and NECO CBT Software for Computers and Laptops - Candidates, Schools, Centres, Resellers - 100% Offline -Download Now

Correct Answer: Option C

Explanation

At 20^oC
0.34 mol/dm of the salt dissolve
= 0.34 * 101 = 34.34gm
Of the salt dissolved.
∴ 34.34gm dissolve is 1,000cm³
If only 250 cm³ is the required mass
X = (250/1000) * 34.34
= 8.555gm
If only 3.40gm of the salt dissolved ,the solution is unsaturated

Previous Next

Go back to Chem classroom

Report an Error Ask A Question Download App