Cu\(_2\)S(s) + O\(_2\)(g) → 2CU(s) + SO\(_2\)(g)
What is the change in the oxidation number of copper in the reaction above?

Allsaint

10 years ago

Here is an explanation:

The CU2O is Copper I oxide,therefore it has been reduced to Cu at the oxidation state of zero.

REF: Comprehensive Certificate Chemistry,page 144

Aderonke2002

1 year ago

i thought the oxidation number for cu in the RHS is +1 and the LHS is +2