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PCl5(g) ↔ PCl3(g) + Cl2(g) In the reaction above, a decrease in pressure will

Chemistry
JAMB 2002

PCl5(g) ↔ PCl3(g) + Cl2(g)
In the reaction above, a decrease in pressure will

  • A. Decelerate the reaction
  • B. Increase the yield of PCl3
  • C. Increase the yield of PCl5
  • D. Accelerate the reaction
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Correct Answer: Option B
Explanation

First, calculate the total number of number of moles of gaseous species only, on both sides.

i.e  1 mole on the LHS  while 2 moles on RHS.

An increase in pressure will favour the side with the lesser value of the total number of moles while a decrease in pressure will favour the side with the higher number of moles i.e the RHS. Hence,increasing the yield of PCl\(_3\).


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