What amount of mercury would be liberated if the same quantity of electricity that liberates 0.65g of zinc is applied?

Ola1000

12 years ago

0.65/65=0.02mole. 0.02mole of zn »»»» 2F. X mole of Hg»»»» 1F. X=0.02*1/2=0.01. Remember mole=g/molar mass. 0.01=g/201. g=2.01 dats it

Penishair

3 years ago

65g from where???

chijioke7

7 years ago

The answer is supposed to be 2.01, the most stable ion of mercury is Hg²⁺ not Hg⁺

Ntemart

3 months ago

simply use
formula:
C1m1/M1=C2m2/M2

C1=Hg=2+, C2=Zn=2+
m1=x=m1, m2=0.65
M1=200, M2=65

2×m1/200=2×0.65/65
cross multiply
2×65×m1=2×200×0.65
130m1=260
m1=2

Hopelary

1 year ago

Pls how come about d 65, bcos d only value I'm seeing is 0.65

amaikpu

2 years ago

pls someone should help and explain I don't understand

VinMed

3 years ago

Hg is divalent so the answer dhould be option A

Award

3 years ago

Very correct 💯%

Finesse11

3 weeks ago

I totally forgot the molar mass of zn and hg😪😫
but I still got the right answer 😝😌

oatcrown

3 months ago

I don't understand this explanation

Dawakiru

2 years ago

Mercury has two electrons in it's outtermost shell. Which should be expressed as. Hg²+ +2ē.
That is, it will take 2Farad to displace 200.59 molar mass of mercury.
In essence, the answer is A: 2.01

Ola1000

12 years ago

Ans 2.01

agentmino

2 years ago

i dont understand anything at all

awusiobi

9 years ago

the answer is correct

BroTolu

4 years ago

it's Hg²+

2.01g