\(C_{12}H_{22}O_{11(s)} + H_2SO_{4(aq)} → 12C(s) + 11H_2O(l) + H_2SO_{4(aq)}\)
In the reaction above, tetraoxosulphate (VI) acid function as
A dehydrating agent
An oxidizing agent
A reducing agent
A catalyst
Explanation
Video Explanation
Post your Contribution
Discussions (9)
most of you might be confuse, A or D. here is the explanation:
A dehydrating agent is a substance that dries or removes water from a material.
while a catalyst speeds up reaction or increase the rate of reaction without itself being consumed.
so as u can see from the question; C12H22O11(s) + H2SO4(aq) 12C(s) + 11H2O(l) + H2SO4(aq)
water was removed from sucrose to form on its own: 11H20(l).
so the answer is correct . A
A dehydrating agent is a substance that removes water molecules from a compound. In this case, sulfuric acid removes the water molecules from sucrose, leaving behind solid carbon.
