\(C_{12}H_{22}O_{11(s)} + H_2SO_{4(aq)} → 12C(s) + 11H_2O(l) + H_2SO_{4(aq)}\)
In the reaction above, tetraoxosulphate (VI) acid function as
A dehydrating agent is a substance that dries or removes water from a substance.
so when sulphuric acid with sugar, the sugar is charred by the removal of water, \(C_{12}H_{22}O_{11(s)} + H_2SO_{4(aq)} → 12C(s) + 11H_2O_{(l}) + H_2SO_{4(aq)}\)
the sulphuric acid is serving as a dehydrating agent.
There is an explanation video available below.
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