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2SO\(_2\)(g) + O\(_2\)(g) ↔ 2SO\(_3\)(g) ΔH = -189 kJ mol-1 The equilibrium constant for the...

Chemistry
JAMB 2001

2SO\(_2\)(g) + O\(_2\)(g) ↔ 2SO\(_3\)(g)
ΔH = -189 kJ mol-1
The equilibrium constant for the reaction above is increased by?

  • A. decreasing the temperature of the system
  • B. decrease the pressure of the system
  • C. The addition of a catalyst to the system
  • D. Increasing the surface area of the vessel
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Correct Answer: Option A
Explanation

Decrease in temperature favors in Equilibrium Constant[k] for this exothermic reaction. 

The only factor that can affect an equilibrium constant is temperature:

  • Endothermic reactions

    Increasing the temperature increases the equilibrium constant, and decreasing the temperature decreases it.

  • Exothermic reactions

    Increasing the temperature decreases the equilibrium constant, and decreasing the temperature increases it. - Option A

There is an explanation video available below.


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Explanation Video

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