P(g) + Q(g) ↔ 3R(s) + S(g) ΔH is negative
Which of the following will increase the yield of R?

a

Using a larger close vessel

b

Increasing the temperature

c

Removing some S

d

Adding a positive catalyst

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Explanation

Correct Option
c

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Discussions (6)

Naeroxide
3 years ago

in equilibrium only gases are involved the products contains (S) only as gas so removing some (S) would decrease the concentration of the product and hereby making the reactant species more concentrated. Equilibrium position always moves from high concentration to low concentration . so the equilibrium position will shift from roght to left favouring the fromation of (R)

MosesCharles
4 years ago

Reducing the temperature, favours the forward reaction i.e more product formation

princehandsome
2 years ago

in equilibrium only gases are involved the products contains (S) only as gas so removing some (S) would decrease the concentration of the product and hereby making the reactant species more concentrated. Equilibrium position always moves from high concentration to low concentration . so the equilibrium position will shift from roght to left favouring the fromation of (R)

Cantseemee
2 months ago

A change in enthalpy being negative is an exothermic reaction not endothermic

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