The pOH of a solution of 0.25 mol dm\(^{-3}\) of hydrochloric acid is

flintg

10 years ago

The hydrogen ion concen.(H+),of the acid is 0.25moldm3 ie(H)=0.25

but ph=-log{H+}

ie pH=-Log{0.25}

=-log{2.5*10`}

=-0.398+1=0.602

but pH+pOH=14

i.e 0.60+pOH=14

^pOH=14-0.60



=13.40

MODESTUSS OGUAMA

10 years ago

thanks but how can you solve the -log(0.25) without the use of calc?

Anela

1 year ago

I made use of two(2) formulae here
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Shakirullah

3 years ago

Pls Admin.... There are no special key functions on the calculator that will be provided on the system on the D-day...
pls if if you can put us through on how to solve it without using calculator....

Or anyone that knows it better...

pls this is important...

@materamabilis01

3 months ago

there is no log in the calculator.

steve2008

1 year ago

calculator no dey for jamb ohh

suliamon25temi

2 months ago

how did we get POH has 14

Okosunjoel

1 year ago

give me a video of the explanation please 🥺

adeleke olamide anass

10 years ago

i don't understand

victorchidubem

11 years ago

i don't get it

OluwatobilobaAdeagbo

1 year ago

it's well

amaikpu

2 years ago

pls i don't understand ooo

itzprincessluisa

3 months ago

I don't also get

Angelife

7 years ago

Why +1 why not -1 ,it says 10 raised to power -1 why u changing it to +1 that's all I wanna know.. D correct option is D not that answer don't change - to + anyhow .. 10^-1 is -1


pH = -log [H+]

. = - (log 25 * 10^-1]
. - (log 25 + log 10^-1 )
-(1.398 + (-1)
. - (1.398-1)
-(0.398)

14-(-0.398)
14+0.398

=14.40

SMARTADEYEMI

1 year ago

The video content doesn't match the question