1s2 2s22p6 3s2 3p6 4s2 3d2
1s2 2s22p6 3s2 3p6 4s2 3d1
1s2 2s22p6 3s2 3p6
1s2 2s22p6 3s2 3p6 3d2
Explanation
Video Explanation
Post your Contribution
Discussions (40)
That is titanium
The electronic configuration of titanium in it's ground state is
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d²
But titanium is a transition element, and first row transition elements lose electrons first from the 4s orbital before losing electrons from the 3d orbital. The electronic configuration of Ti²⁺ is
1s² 2s² 2p⁶ 3s² 3p⁶ 3d²
As you can see, titanium lost the two electrons from the 4s orbital
NB: The 4s orbital is the outermost orbital and the 3d orbital is just the highest energy orbital, but metals lose electrons from the outermost orbital.
The answer is not in the options
The element is titanium, which has 22 electrons but hence it has formed an ion of 2 (it loses 2 electron to form an ion). Its number of electron becomes 20 instead of 22 and can now be configured as calcium. So the option is correct.
To calculate no of electrons on an ion, formula= Atomic no.- charge,=22-2,=20. therefore, new electron configuration is 1s²2s²2p⁶3s²3p⁶4s²
the answer supposed to be calcium which stopped at 4S²
remember the charge is+2 so it's going to reduce ok.
I got the answer doing my test Even due they did mistake because from the options no other close answer apart from it.
