The salt that reacts with dilute hydrochloric acid to produce a pungent smelling gas which decolourizes acidified purple potassium tetraoxomanganate (VII) solution is

mc.Jeremiah

6 years ago

The answer is correct
Na2SO3+2HCl-----2NaCl+H2O+SO2
SO2 is the gas that decolourizes KMnO4.
If you are not convinced please make reference to your textbook or check google.

Messi333333

5 years ago

Na2so3 is the salt that reacts with dilute hydrochloric acid to produce a pungent smelling gas which decolourizes acidified purple potassium tetraoxonanganate (VII) solution, this gas is SO2.

Olive_dwyer

2 years ago

The answer is not C because with H2S there would be yellow deposits of sulphur which is not stated in the question, so B is the best option to chosse

anjolatee

7 years ago

Myschool the answer for d above question is c bcos Na2s react with Hcl to give H2s

Kenhinde

3 years ago

I don't know maybe this will and the question...so,SO
2
​
is a colourless suffocating gas. Acidified potassium manganate(VII) is a strong oxidising agent so it can be used to oxidise substances. If a reaction occurs a colour change will be seen. Potassium manganate(VII) is deep purple and when it is reduced, it becomes colourless.

If sulphur dioxide gas is bubbled into the purple acidified manganate(VII) solution, the manganate(VII) is decolourised showing that the manganate(VII) ions are being reduced by the sulphur dioxide gas to Mn
2+
ions.

oluwaseun mercy

9 years ago

y not choosing A

Efranklyn

4 years ago

Both have pungent smell and can reduce an oxidizing agent but have we all noticed that SO2 does not reduce unless water is present
Therefore I think Na2S is close to the answer

Korede2002

6 years ago

Myschool, the correct answer is C.