If 24.83 cm³ of 0.15 M NaOH is titrated to its end point with 39.45 cm³
of HCl, what is the molarity of the HCl?

Ajanaku Samiat

11 years ago

Ma*Va/Mb*Vb=Na/Nb

Ma*39.45/0.15*24.83=1/1

Ma=0.094M, the correct ans is A

Tumise17

1 year ago

M1.V1=M2.V2
0.15*24.83=39.45*M2
M2=0.15*24.83/39.45
=0.0944M

Ibto

5 years ago

how do we know the ratio