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If 24.83 cm3 of 0.15 M NaOH is titrated to its end point with 39.45...

Chemistry
JAMB 1987

If 24.83 cm3 of 0.15 M NaOH is titrated to its end point with 39.45 cm3
of HCl, what is the molarity of the HCl?
  • A. 0.094 M
  • B. 0.150 M
  • C. 0.940 M
  • D. 1.500 M
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Correct Answer: Option A
Explanation
NaOH + HCl → NaCl + H2O moles ratio = 1/1
↔ (MaVa) / Mb x 39.45 = 0.094

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Project Topics and Materials, Post-UTME past questions - Download now or upload yours to get paid
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