RS(aq) + HF(aq) → RF(s) + HS(aq) ΔH = -65.7 kj mol(-1). From the equation...

Chemistry

JAMB 1999

RS_(aq) + HF_(aq) → RF_(s) + HS_(aq)
ΔH = -65.7 kj mol^(-1).
From the equation above, it can be deduced that

A. the heat content of the reactants is lower than that of the products
B. the heat content of the reactants is higher than that of the products
C. the reaction is slow
D. a large amount of heat is absorbed

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Correct Answer: Option B

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RS(aq) + HF(aq) → RF(s) + HS(aq) ΔH = -65.7 kj mol(-1). From the equation...

Correct Answer: Option B

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