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RS(aq) + HF(aq) → RF(s) + HS(aq) ΔH = -65.7 kj mol(-1). From the equation...

Chemistry
JAMB 1999

RS(aq) + HF(aq) → RF(s) + HS(aq)
ΔH = -65.7 kj mol(-1).
From the equation above, it can be deduced that
  • A. the heat content of the reactants is lower than that of the products
  • B. the heat content of the reactants is higher than that of the products
  • C. the reaction is slow
  • D. a large amount of heat is absorbed
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Correct Answer: Option B
Explanation
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