Which of the following silver halides is readily soluble in ammonium hydroxide?

a

Agl

b

AgBr

c

AgCl

d

AgF

e

None of the above

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Correct Option
c

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Discussions (11)

Bright002
3 years ago

But Flourine is most reactive and it can also react with NH4OH to give HF

aishat491
7 years ago

y this ans pls

Sammyporsche123
2 years ago

Among the silver halides (AgI, AgBr, AgCl, and AgF), silver chloride (AgCl) is the one that is readily soluble in ammonium hydroxide (NH4OH). Silver iodide (AgI) does not dissolve even with concentrated ammonia. So, the correct answer is **C. AgCl**.

Joseph
3 months ago

Correct

cooldayve16
1 year ago

damn

Olive_dwyer
2 years ago

AgG is readily soluble in ammonium hydroxide. This is because, when
A
g
F
dissociates, the
F

, a weak base, is consumed to produce the weak acid
H
F
. Therefore, further dissolution of
A
g
F
will be favored. This is not similar with
A
g
C
l
,
A
g
B
r
, and
A
g
I
because their anions are conjugate bases of strong acids

the answer should be AgF

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