a
Agl
b
AgBr
c
AgCl
d
AgF
e
None of the above
Explanation
Correct Option
cNo explanation available
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Discussions (11)

Sammyporsche123
2 years ago
Among the silver halides (AgI, AgBr, AgCl, and AgF), silver chloride (AgCl) is the one that is readily soluble in ammonium hydroxide (NH4OH). Silver iodide (AgI) does not dissolve even with concentrated ammonia. So, the correct answer is **C. AgCl**.

Olive_dwyer
2 years ago
AgG is readily soluble in ammonium hydroxide. This is because, when
A
g
F
dissociates, the
F
−
, a weak base, is consumed to produce the weak acid
H
F
. Therefore, further dissolution of
A
g
F
will be favored. This is not similar with
A
g
C
l
,
A
g
B
r
, and
A
g
I
because their anions are conjugate bases of strong acids


