What mass of a divalent metal M (atomic mass = 40) would react with excess hydrochloric acid to liberate 224cm^3 dry hydrogen gas measured at S.T.P?

ICEDOK

5 years ago

First convert your cm3 to dm3 I.e
224/1000=0.224
So if 40 - 22.4dm3
X - 0.224
Cross multiply and make x the subject of the formula
X = 0.224×40/22.4
X = 0.4g
Thanks.
Hope this helps

Lydwina

10 years ago

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Anj0la

3 years ago

The question is incomplete:Here is thr complete one
What mass of a divalent metal. M (atomic mass 40) would react with excess hydrochloric acid to liberate 22.4cm3 of dry hydrogen gas measured as s.t.p.?

CenSmart

6 years ago

What mass of a divalent metal M (atomic mass= 40)
would react with excess hydrochloric acid to liberate
22 cm3 of dry hydrogen gas measured as S.T.P?

temi06tayo

4 years ago

I agree with this

Emmanuel24458

2 years ago

Since it's a divalent elements x is the element
2hcl + x ------xcl2 + h2
224cm/1000 = 0.224
V/22.4= mole

0.224/22.4 =0.01mol

1mole of x. --- 1mol of h
Xmol of x. ----0.01mol

So =0.4g so the element is calcium

Leohh

6 months ago

omor textbook said 8.0
it's 0.4

okekeephraim1

2 years ago

No mass or volume of the gas hydrogen to work or calculate with......?

adepojuisaiah

5 years ago

we need to see the solvings of the calculation works

Jojo4pf

3 years ago

needs a chemical equation maybe

Cletusclevica

5 years ago

Mass/molar mass* molarvolume/volume.
So: let mass = m and volume=224÷1000=0.224
: m/40*22.4/0.224=0.4g